Use TikTok Publish with TikTok Publish via the Muapi REST API. Pay per generation — no subscription needed.
POST https://api.muapi.ai/api/v1/tiktok-publishSubmit a job with your MuApi API key in the x-api-key header, then poll https://api.muapi.ai/api/v1/predictions/{request_id}/result until status is completed.
| Name | Type | Required | Description |
|---|---|---|---|
| account_id | integer | Yes | ID of the connected TikTok account. |
| media_url | string | Yes | Public URL of the video to upload. |
| title | string | No | Video caption (max 150 chars).Default: "" |
| privacy_level | string | No | Options: PUBLIC_TO_EVERYONE, MUTUAL_FOLLOW_FRIENDS, FOLLOWER_OF_CREATOR, SELF_ONLYDefault: "PUBLIC_TO_EVERYONE" |
| allow_comment | boolean | No | Default: true |
| allow_duet | boolean | No | Default: true |
| allow_stitch | boolean | No | Default: true |
| is_ai_generated | boolean | No | Mark as AI-generated.Default: false |
REQUEST_ID=$(curl -s -X POST https://api.muapi.ai/api/v1/tiktok-publish \
-H "x-api-key: $MUAPI_API_KEY" \
-H "Content-Type: application/json" \
-d '{"account_id":0,"media_url":"https://example.com/your-media_url"}' | jq -r .request_id)
curl -s https://api.muapi.ai/api/v1/predictions/$REQUEST_ID/result -H "x-api-key: $MUAPI_API_KEY"import os, time, requests
API = "https://api.muapi.ai/api/v1"
headers = {"x-api-key": os.environ["MUAPI_API_KEY"]}
r = requests.post(f"{API}/tiktok-publish", headers=headers, json={"account_id":0,"media_url":"https://example.com/your-media_url"})
request_id = r.json()["request_id"]
while True:
res = requests.get(f"{API}/predictions/{request_id}/result", headers=headers).json()
if res["status"] == "completed":
print(res["outputs"]); break
if res["status"] == "failed":
raise RuntimeError(res.get("error"))
time.sleep(3)Full docs and agent/MCP integration: llms.txt. Get an API key at muapi.ai/access-keys.